0.0915t^2+-0.93t+1.705=0

Solution for 0.0915t^2+-0.93t+1.705=0 equation:

0.0915t^2+-0.93t+1.705=0

We add all the numbers together, and all the variables

0.0915t^2-0.93t=0

a = 0.0915; b = -0.93; c = 0;
Δ = b2-4ac
Δ = -0.932-4·0.0915·0
Δ = 0.8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.93)-\sqrt{0.8649}}{2*0.0915}=\frac{0.93-\sqrt{0.8649}}{0.183}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.93)+\sqrt{0.8649}}{2*0.0915}=\frac{0.93+\sqrt{0.8649}}{0.183}
$